Set 1 4 questions ▶

The above is a schematic diagram of walkways (indicated by all the straight-lines) and lakes(3 of them, each in the shape of rectangles – shaded in the diagram) of a gated area. Different points on the walkway are indicated by letters (A through P) with distances being OP = 150 m, ON = MN = 300 m, ML = 400 m, EL = 200 m, DE = 400 m.

The following additional information about the facilities in the area is known.

1. The only entry/exit point is at C.

2. There are many residences within the gated area; all of them are located on the path AH and ML with four of them being at A, H, M, and L.

3. The post office is located at P and the bank is located at B.

Q1 One resident whose house is located at L, needs to visit the post office as well as the b… MCQ ▶

One resident whose house is located at L, needs to visit the post office as well as the bank. What is the minimum distance (in m) he has to walk starting from his residence and returning to his residence after visiting both the post office and the bank?

[Note: In actual paper CAT 2024, two options (3) and (4) i.e., 3000 were same.]

A.

3200

B.

2700

C.

3000

D.

3400

Correct answer: A.

3200

Q2 One person enters the gated area and decides to walk as much as possible before leaving t… MCQ ▶

One person enters the gated area and decides to walk as much as possible before leaving the area without walking along any path more than once and always walking next to one of the lakes. Note that he may cross a point multiple times. How much distance (in m) will he walk within the gated area?

A.

3200

B.

3000

C.

2800

D.

3800

Correct answer: D.

3800

Q3 One resident takes a walk within the gated area starting from A and returning to A withou… TITA ▶

One resident takes a walk within the gated area starting from A and returning to A without going through any point (other than A) more than once. What is the maximum distance (in m) she can walk in this way?

Answer: 5100

Q4 Visitors coming for morning walks are allowed to enter as long as they do not pass by any… TITA ▶

Visitors coming for morning walks are allowed to enter as long as they do not pass by any of the residences and do not cross any point (except C) more than once.What is the maximum distance (in m) that such a visitor can walk within the gated area?

Answer: 3500

Set 2 4 questions ▶

Alia, Badal, Clive, Dilshan, and Ehsaan played a game in which each asks a unique question to all the others and they respond by tapping their feet, either once or twice or thrice. One tap means “Yes”, two taps mean “No”, and three taps mean “Maybe”.

A total of 40 taps were heard across the five questions. Each question received at least one “Yes”, one “No”, and one “Maybe.”

The following information is known.

1. Alia tapped a total of 6 times and received 9 taps to her question. She responded “Yes” to the questions asked by both Clive and Dilshan.

2. Dilshan and Ehsaan tapped a total of 11 and 9 times respectively. Dilshan responded “No” to Badal.

3. Badal, Dilshan, and Ehsaan received equal number of taps to their respective questions.

4. No one responded “Yes” more than twice.

5. No one’s answer to Alia’s question matched the answer that Alia gave to that person’s question. This was also true for Ehsaan.

6. Clive tapped more times in total than Badal.

Q5 How many taps did Clive receive for his question? TITA ▶

How many taps did Clive receive for his question?

Answer: 7

Step 1:

Here, one tap represents "Yes", two taps represent "No", and three taps represent "Maybe".

Since every question received at least one "Yes", one "No", and one "Maybe", each person must have received more than 6 taps in total.

Using Conditions (1) and (4), Alia gave 2 "Yes" responses and 2 "No" responses.

From Condition (6), the combined number of taps made by Badal and Clive is:

40 − (6 + 11 + 9) = 14

Also, Clive made more taps than Badal. Along with Condition (4), this implies that Badal made 6 taps, while Clive made 8 taps.

Now, applying Condition (3), let the number of taps received by Badal, Dilshan, and Ehsaan be x each.

Therefore, the taps received by Clive are:

40 − 9 − 3x = 31 − 3x

Since every person received more than 6 taps,

31 − 3x > 6

which gives x < 8.33. Hence, x can only be 7 or 8.

If x = 7, then Clive would receive 31 − 21 = 10 taps, which is not possible because Badal answered either "Yes" or "No" to Clive's question.
Therefore, x = 8, giving Clive = 31 − 24 = 7 taps, which satisfies all the conditions.

The deductions obtained so far are summarized in the table below.

Step 2:

Using Condition (5), no person's response to Alia's question matched the response that Alia gave to that person's question. The same condition also applies to Ehsaan.

Applying this constraint completes the entire arrangement, which is shown in the final table below.

Hence, Clive received 7 taps for his question.

Q6 Which two people tapped an equal number of times in total? MCQ ▶

Which two people tapped an equal number of times in total?

A.

Alia and Badal

B.

Clive and Ehsaan

C.

Dilshan and Clive

D.

Badal and Dilshan

Correct answer: A.

Alia and Badal

Step 1:

Here, one tap represents "Yes", two taps represent "No", and three taps represent "Maybe".

Since every question received at least one "Yes", one "No", and one "Maybe", each person must have received more than 6 taps in total.

Using Conditions (1) and (4), Alia gave 2 "Yes" responses and 2 "No" responses.

From Condition (6), the combined number of taps made by Badal and Clive is:

40 − (6 + 11 + 9) = 14

Also, Clive made more taps than Badal. Along with Condition (4), this implies that Badal made 6 taps, while Clive made 8 taps.

Now, applying Condition (3), let the number of taps received by Badal, Dilshan, and Ehsaan be x each.

Therefore, the taps received by Clive are:

40 − 9 − 3x = 31 − 3x

Since every person received more than 6 taps,

31 − 3x > 6

which gives x < 8.33. Hence, x can only be 7 or 8.

If x = 7, then Clive would receive 31 − 21 = 10 taps, which is not possible because Badal answered either "Yes" or "No" to Clive's question.
Therefore, x = 8, giving Clive = 31 − 24 = 7 taps, which satisfies all the conditions.

The deductions obtained so far are summarized in the table below.

Step 2:

Using Condition (5), no person's response to Alia's question matched the response that Alia gave to that person's question. The same condition also applies to Ehsaan.

Applying this constraint completes the entire arrangement, which is shown in the final table below.

Alia and Badal tapped an equal number of times in total.

Q7 What was Clive’s response to Ehsaan’s question? MCQ ▶

What was Clive’s response to Ehsaan’s question?

A.

No

B.

Maybe

C.

Cannot be determined

D.

Yes

Correct answer: A.

No

Step 1:

Here, one tap represents "Yes", two taps represent "No", and three taps represent "Maybe".

Since every question received at least one "Yes", one "No", and one "Maybe", each person must have received more than 6 taps in total.

Using Conditions (1) and (4), Alia gave 2 "Yes" responses and 2 "No" responses.

From Condition (6), the combined number of taps made by Badal and Clive is:

40 − (6 + 11 + 9) = 14

Also, Clive made more taps than Badal. Along with Condition (4), this implies that Badal made 6 taps, while Clive made 8 taps.

Now, applying Condition (3), let the number of taps received by Badal, Dilshan, and Ehsaan be x each.

Therefore, the taps received by Clive are:

40 − 9 − 3x = 31 − 3x

Since every person received more than 6 taps,

31 − 3x > 6

which gives x < 8.33. Hence, x can only be 7 or 8.

If x = 7, then Clive would receive 31 − 21 = 10 taps, which is not possible because Badal answered either "Yes" or "No" to Clive's question.
Therefore, x = 8, giving Clive = 31 − 24 = 7 taps, which satisfies all the conditions.

The deductions obtained so far are summarized in the table below.

Step 2:

Using Condition (5), no person's response to Alia's question matched the response that Alia gave to that person's question. The same condition also applies to Ehsaan.

Applying this constraint completes the entire arrangement, which is shown in the final table below.

Clive’s response to Ehsaan’s question was ‘No’.

Q8 How many “Yes” responses were received across all the questions? TITA ▶

How many “Yes” responses were received across all the questions?

Answer: 6

Step 1:

Here, one tap represents "Yes", two taps represent "No", and three taps represent "Maybe".

Since every question received at least one "Yes", one "No", and one "Maybe", each person must have received more than 6 taps in total.

Using Conditions (1) and (4), Alia gave 2 "Yes" responses and 2 "No" responses.

From Condition (6), the combined number of taps made by Badal and Clive is:

40 − (6 + 11 + 9) = 14

Also, Clive made more taps than Badal. Along with Condition (4), this implies that Badal made 6 taps, while Clive made 8 taps.

Now, applying Condition (3), let the number of taps received by Badal, Dilshan, and Ehsaan be x each.

Therefore, the taps received by Clive are:

40 − 9 − 3x = 31 − 3x

Since every person received more than 6 taps,

31 − 3x > 6

which gives x < 8.33. Hence, x can only be 7 or 8.

If x = 7, then Clive would receive 31 − 21 = 10 taps, which is not possible because Badal answered either "Yes" or "No" to Clive's question.
Therefore, x = 8, giving Clive = 31 − 24 = 7 taps, which satisfies all the conditions.

The deductions obtained so far are summarized in the table below.

Step 2:

Using Condition (5), no person's response to Alia's question matched the response that Alia gave to that person's question. The same condition also applies to Ehsaan.

Applying this constraint completes the entire arrangement, which is shown in the final table below.

Six ‘’Yes” responses were received across all the questions.

Set 3 5 questions ▶

Two students, Amiya and Ramya are the only candidates in an election for the position of class representative. Students will vote based on the intensity level of Amiya's and Ramya's campaigns and the type of campaigns they run. Each campaign is said to have a level of 1 if it is a staid campaign and a level of 2 if it is a vigorous campaign. Campaigns can be of two types, they can either focus on issues, or on attacking the other candidate. If Amiya and Ramya both run campaigns focusing on issues, then

• The percentage of students voting in the election will be 20 times the sum of the levels of campaigning of the two students. For example, if Amiya and Ramya both run vigorous campaigns, then 20 × (2 + 2)%, that is, 80% of the students will vote in the election.

• Among voting students, the percentage of votes for each candidate will be proportional to the levels of their campaigns. For example, if Amiya runs a staid (i.e., level 1) campaign while Ramya runs a vigorous (i.e., level 2) campaign, then Amiya will receive 1/3 of the votes cast, and Ramya will receive the other 2/3.

The above-mentioned percentages change as follows if at least one of them runs a campaign attacking their opponent.

• If Amiya runs a campaign attacking Ramya and Ramya runs a campaign focusing on issues, then 10% of the students who would have otherwise voted for Amiya will vote for Ramya, and another 10% who would have otherwise voted for Amiya, will not vote at all.

• If Ramya runs a campaign attacking Amiya and Amiya runs a campaign focusing on issues, then 20% of the students who would have otherwise voted for Ramya will vote for Amiya, and another 5% who would have otherwise voted for Ramya, will not vote at all.

• If both run campaigns attacking each other, then 10% of the students who would have otherwise voted for them had they run campaigns focusing on issues, will not vote at all.

Q9 If both of them run staid campaigns attacking the other, then what percentage of students… MCQ ▶

If both of them run staid campaigns attacking the other, then what percentage of students will vote in the election?

A.

64%

B.

36%

C.

60%

D.

40%

Correct answer: B.

36%

Step 1:

The voter turnout percentage is calculated as:

Turnout (%) = 20 × (Sum of the campaign intensity levels of the two candidates)

Thus, the turnout for each combination is:

Amiya (Staid) vs Ramya (Staid): 20 × (1 + 1)% = 40%
Amiya (Staid) vs Ramya (Vigorous): 20 × (1 + 2)% = 60%
Amiya (Vigorous) vs Ramya (Staid): 20 × (2 + 1)% = 60%
Amiya (Vigorous) vs Ramya (Vigorous): 20 × (2 + 2)% = 80%

The corresponding vote distribution is:

Staid vs Staid: Amiya = 1/2, Ramya = 1/2
Staid vs Vigorous: Amiya = 1/3, Ramya = 2/3
Vigorous vs Staid: Amiya = 2/3, Ramya = 1/3
Vigorous vs Vigorous: Amiya = 1/2, Ramya = 1/2

Step 2:

From the given conditions, the vote transfers are:

Attack vs Attack: 10% of Amiya's votes shift to No Vote, and 10% of Ramya's votes also shift to No Vote.
Attack vs Issues: 10% of Amiya's votes are transferred to Ramya.
Issues vs Attack: 20% of Ramya's votes move to Amiya, while 5% of Ramya's votes shift to No Vote.
Issues vs Issues: 10% of Amiya's votes move to No Vote.

The campaign intensity of both candidates is 1.

Therefore, the voter turnout is:

20 × (1 + 1)% = 40%

Initially, each candidate receives half of the votes, i.e., 20% each.

Since 10% of each candidate's votes are lost, each finally secures:

20% × 90% = 18%

Hence, the total percentage of students who cast a valid vote in the election is:

18% + 18% = 36%

Q10 What is the minimum percentage of students who will vote in the election? MCQ ▶

What is the minimum percentage of students who will vote in the election?

A.

36%

B.

40%

C.

32%

D.

38%

Correct answer: A.

36%

Step 1:

The voter turnout percentage is calculated as:

Turnout (%) = 20 × (Sum of the campaign intensity levels of the two candidates)

Thus, the turnout for each combination is:

Amiya (Staid) vs Ramya (Staid): 20 × (1 + 1)% = 40%
Amiya (Staid) vs Ramya (Vigorous): 20 × (1 + 2)% = 60%
Amiya (Vigorous) vs Ramya (Staid): 20 × (2 + 1)% = 60%
Amiya (Vigorous) vs Ramya (Vigorous): 20 × (2 + 2)% = 80%

The corresponding vote distribution is:

Staid vs Staid: Amiya = 1/2, Ramya = 1/2
Staid vs Vigorous: Amiya = 1/3, Ramya = 2/3
Vigorous vs Staid: Amiya = 2/3, Ramya = 1/3
Vigorous vs Vigorous: Amiya = 1/2, Ramya = 1/2

Step 2:

From the given conditions, the vote transfers are:

Attack vs Attack: 10% of Amiya's votes shift to No Vote, and 10% of Ramya's votes also shift to No Vote.
Attack vs Issues: 10% of Amiya's votes are transferred to Ramya.
Issues vs Attack: 20% of Ramya's votes move to Amiya, while 5% of Ramya's votes shift to No Vote.
Issues vs Issues: 10% of Amiya's votes move to No Vote.

To obtain the minimum voting percentage, both candidates must choose a staid campaign.

In this case, the voter turnout is 40%, with each candidate initially receiving 20% of the votes.

Since both candidates attack each other, 10% of each candidate's votes are lost.

Thus, each candidate finally secures:

20% × 90% = 18%

Hence, the minimum percentage of students who cast a valid vote in the election is:

18% + 18% = 36%

Q11  If Amiya runs a campaign focusing on issues, then what is the maximum percentage of… MCQ ▶

If Amiya runs a campaign focusing on issues, then what is the maximum percentage of votes that she can get?

A.

44%

B.

40%

C.

48%

D.

36%

Correct answer: C.

48%

Step 1:

The voter turnout percentage is calculated as:

Turnout (%) = 20 × (Sum of the campaign intensity levels of the two candidates)

Thus, the turnout for each combination is:

Amiya (Staid) vs Ramya (Staid): 20 × (1 + 1)% = 40%
Amiya (Staid) vs Ramya (Vigorous): 20 × (1 + 2)% = 60%
Amiya (Vigorous) vs Ramya (Staid): 20 × (2 + 1)% = 60%
Amiya (Vigorous) vs Ramya (Vigorous): 20 × (2 + 2)% = 80%

The corresponding vote distribution is:

Staid vs Staid: Amiya = 1/2, Ramya = 1/2
Staid vs Vigorous: Amiya = 1/3, Ramya = 2/3
Vigorous vs Staid: Amiya = 2/3, Ramya = 1/3
Vigorous vs Vigorous: Amiya = 1/2, Ramya = 1/2

Step 2:

From the given conditions, the vote transfers are:

Attack vs Attack: 10% of Amiya's votes shift to No Vote, and 10% of Ramya's votes also shift to No Vote.
Attack vs Issues: 10% of Amiya's votes are transferred to Ramya.
Issues vs Attack: 20% of Ramya's votes move to Amiya, while 5% of Ramya's votes shift to No Vote.
Issues vs Issues: 10% of Amiya's votes move to No Vote.

To maximize Amiya's vote share, the voter turnout must be 80%.

Initially, both Amiya and Ramya receive 40% of the votes.

Under the given conditions, 20% of Ramya's votes are transferred to Amiya.

Therefore, Amiya's final vote share is:

= 40% + 20% of 40%

= 40% + 8%

= 48%

Hence, the maximum percentage of votes that Amiya can receive is 48%.

Q12 If Ramya runs a campaign attacking Amiya, then what is the minimum percentage of votes th… MCQ ▶

If Ramya runs a campaign attacking Amiya, then what is the minimum percentage of votes that she is guaranteed to get?

A.

12%

B.

18%

C.

15%

D.

30%

Correct answer: C.

15%

Step 1:

The voter turnout percentage is calculated as:

Turnout (%) = 20 × (Sum of the campaign intensity levels of the two candidates)

Thus, the turnout for each combination is:

Amiya (Staid) vs Ramya (Staid): 20 × (1 + 1)% = 40%
Amiya (Staid) vs Ramya (Vigorous): 20 × (1 + 2)% = 60%
Amiya (Vigorous) vs Ramya (Staid): 20 × (2 + 1)% = 60%
Amiya (Vigorous) vs Ramya (Vigorous): 20 × (2 + 2)% = 80%

The corresponding vote distribution is:

Staid vs Staid: Amiya = 1/2, Ramya = 1/2
Staid vs Vigorous: Amiya = 1/3, Ramya = 2/3
Vigorous vs Staid: Amiya = 2/3, Ramya = 1/3
Vigorous vs Vigorous: Amiya = 1/2, Ramya = 1/2

Step 2:

From the given conditions, the vote transfers are:

Attack vs Attack: 10% of Amiya's votes shift to No Vote, and 10% of Ramya's votes also shift to No Vote.
Attack vs Issues: 10% of Amiya's votes are transferred to Ramya.
Issues vs Attack: 20% of Ramya's votes move to Amiya, while 5% of Ramya's votes shift to No Vote.
Issues vs Issues: 10% of Amiya's votes move to No Vote.

To determine the minimum vote share that Ramya is guaranteed to receive, the voter turnout must be 40%.

Initially, both Amiya and Ramya receive 20% of the votes.

Since Ramya adopts a campaign that attacks Amiya, 20% of Ramya's votes are transferred to Amiya, while an additional 5% of her votes are lost.

Therefore, Ramya's final vote share is:

= 20% − 20% of 20% − 5% of 20%

= 20% − 4% − 1%

= 15%

Hence, the minimum percentage of votes that Ramya is guaranteed to receive is 15%.

Q13 What is the maximum possible voting margin with which one of the candidates can win? MCQ ▶

What is the maximum possible voting margin with which one of the candidates can win?

A.

28%

B.

26%

C.

29%

D.

20%

Correct answer: C.

29%

Step 1:

The voter turnout percentage is calculated as:

Turnout (%) = 20 × (Sum of the campaign intensity levels of the two candidates)

Thus, the turnout for each combination is:

Amiya (Staid) vs Ramya (Staid): 20 × (1 + 1)% = 40%
Amiya (Staid) vs Ramya (Vigorous): 20 × (1 + 2)% = 60%
Amiya (Vigorous) vs Ramya (Staid): 20 × (2 + 1)% = 60%
Amiya (Vigorous) vs Ramya (Vigorous): 20 × (2 + 2)% = 80%

The corresponding vote distribution is:

Staid vs Staid: Amiya = 1/2, Ramya = 1/2
Staid vs Vigorous: Amiya = 1/3, Ramya = 2/3
Vigorous vs Staid: Amiya = 2/3, Ramya = 1/3
Vigorous vs Vigorous: Amiya = 1/2, Ramya = 1/2

Step 2:

From the given conditions, the vote transfers are:

Attack vs Attack: 10% of Amiya's votes shift to No Vote, and 10% of Ramya's votes also shift to No Vote.
Attack vs Issues: 10% of Amiya's votes are transferred to Ramya.
Issues vs Attack: 20% of Ramya's votes move to Amiya, while 5% of Ramya's votes shift to No Vote.
Issues vs Issues: 10% of Amiya's votes move to No Vote.

Here, the voter turnout is 60%.

Case 1: Amiya secures 40% of the votes, while Ramya secures 20%.

Amiya's final vote share:

= 40% + 20% of 20%

= 44%

Ramya's final vote share:

= 20% − 20% of 20% − 5% of 20%

= 20% − 4% − 1%

= 15%

Therefore, the voting margin is:

44% − 15% = 29%

Case 2: Amiya secures 20% of the votes, while Ramya secures 40%.

Amiya's final vote share:

= 20% + 10% of 20% − 10% of 20%

= 16%

Ramya's final vote share:

= 40% + 10% of 20%

= 42%

Therefore, the voting margin is:

42% − 16% = 26%

Hence, the maximum possible voting margin is 29%.

Set 4 5 questions ▶

Odsville has five firms – Alfloo, Bzygoo, Czechy, Drjbna and Elavalaki. Each of these firms was founded in some year and also closed down a few years later.

Each firm raised Rs. 1 crore in its first and last year of existence. The amount each firm raised every year increased until it reached a maximum, and then decreased until the firm closed down. No firm raised the same amount of money in two consecutive years. Each annual increase and decrease was either by Rs. 1 crore or by Rs. 2 crores.

The table below provides partial information about the five firms.

Q14 For which firm(s) can the amounts raised by them be concluded with certainty in each year? MCQ ▶

For which firm(s) can the amounts raised by them be concluded with certainty in each year?

A.

Only Bzygoo and Czechy and Drjbna

B.

Only Drjbna

C.

Only Czechy and Drjbna

D.

Only Czechy

Correct answer: C.

Only Czechy and Drjbna

Step 1:

Let us determine the annual amount of money raised by each firm.

Brzygoo:

There are two possible distributions of the funds raised (in crores):

Case 1

2012: 1
2013: 2
2014: 3
2015: 1

Case 2

2012: 1
2013: 3
2014: 2
2015: 1

Czechy:

The amounts raised are:

2013: 1
2014: a
2015: b
2016: c
2017: 1

Since the total amount raised is 9 crores,

a + b + c = 9 − 2 = 7

The only possible values satisfying this condition are:

(a, b, c) = (2, 3, 2)

(No other arrangement is possible, as changing the last year of existence would not satisfy the total amount of 7.)

Drjbna:

The yearly amounts raised (in crores) are:

2011: 1
2012: 2
2013: 4
2014: 2
2015: 1

Hence, the exact yearly amounts can be uniquely determined only for Czechy and Drjbna.

Q15 What best can be concluded about the total amount of money raised in 2015? MCQ ▶

What best can be concluded about the total amount of money raised in 2015?

A.

It is either Rs. 7 crores or Rs. 8 crores.

B.

It is either Rs. 8 crores or Rs. 9 crores.

C.

It is exactly Rs. 8 crores.

D.

It is either Rs. 7 crores or Rs. 8 crores or Rs. 9 crores.

Correct answer: A.

It is either Rs. 7 crores or Rs. 8 crores.

Step 1:

Let us determine the possible annual amounts raised by Alfloo and Elavalaki.

Alfloo:

Assume the yearly amounts raised (in crores) are:

2009: 1
2010: 3
2011: 4
2012: 5
2013: 4
2014: 3
2015: 2
2016: 1

This gives the minimum possible amount in 2010, assuming 2015 = 2 crores.

However, the total comes to 23 crores, which is not feasible.

Therefore, the amount raised in 2010 must increase by 1 crore.

The possible distributions are:

Case 1

2009: 1
2010: 2
2011: 3
2012: 4
2013: 5
2014: 3
2015: 2
2016: 1

Case 2

2009: 1
2010: 2
2011: 3
2012: 5
2013: 4
2014: 3
2015: 2
2016: 1

Note: If the amount raised in 2011 were 4 crores, the minimum possible total would be 22 crores (sequence 1-2-4-5-4-3-2-1), which is also not feasible.

Elavalaki:

The possible yearly amounts are:

Case 1

Sub-case 1

2010: 1
2011: 2
2012: 3
2013: 4
2014: 2
2015: 1

Sub-case 2

2010: 1
2011: 2
2012: 4
2013: 3
2014: 2
2015: 1

Case 2

2010: 1
2011: 3
2012: 5
2013: 3
2014: 1

Hence, the amount of money raised in 2015 could be:

= 2 + 1 + 3 + 1 + 1 or 0

= 7 crores or 8 crores.

Q16 What is the largest possible total amount of money (in Rs. crores) that could have been r… TITA ▶

What is the largest possible total amount of money (in Rs. crores) that could have been raised in 2013?

Answer: 17

The largest possible amount of money raised in 2013 (in Rs. crores) by each firm is:

Alfloo: 5
Brzygoo: 3
Czechy: 1
Drjbna: 4
Elavalaki: 4

Therefore, the maximum total amount raised in 2013 is:

= 5 + 3 + 1 + 4 + 4

= 17 crores

Hence, the required answer is 17 crores.

Q17 If Elavalaki raised Rs. 3 crores in 2013, then what is the smallest possible total amount… MCQ ▶

If Elavalaki raised Rs. 3 crores in 2013, then what is the smallest possible total amount of money (in Rs. crores) that could have been raised by all the companies in 2012?

A.

9

B.

11

C.

12

D.

10

Correct answer: B.

11

If Elavalaki raised Rs. 3 crore in 2013, the following two cases are possible:

Case 1

2010: 1
2011: 3
2012: 5
2013: 3
2014: 1
2015: 0

Case 2

2010: 1
2011: 2
2012: 4
2013: 3
2014: 2
2015: 1

Accordingly, the minimum possible amount of money raised by all five companies in 2012 is:

= 4 + 1 + 0 + 2 + 4

= 11 crores.

Q18 If the total amount of money raised in 2014 is Rs. 12 crores, then which of the following… MCQ ▶

If the total amount of money raised in 2014 is Rs. 12 crores, then which of the following is not possible?

A.

Alfloo raised the same amount of money as Bzygoo in 2014.

B.

Alfloo raised the same amount of money as Drjbna in 2013.

C.

Bzygoo raised the same amount of money as Elavalaki in 2013.

D.

Bzygoo raised more money than Elavalaki in 2014.

Correct answer: C.

Bzygoo raised the same amount of money as Elavalaki in 2013.

If the total amount of money raised in 2014 is Rs. 12 crores, the possible amounts raised by the firms in 2014 are:

Alfloo: 3
Brzygoo: 2 or 3
Czechy: 2
Drjbna: 2
Elavalaki: 2 or 1

These values add up to the required total of 12 crores.

Under this arrangement, the statement "Brzygoo raised the same amount of money as Elavalaki in 2013" cannot be satisfied.

Hence, the given statement is not possible.

Set 5 5 questions ▶

Anjali, Bipasha, and Chitra visited an entertainment park that has four rides. Each ride lasts one hour and can accommodate one visitor at one point. All rides begin at 9 am and must be completed by 5 pm except for Ride-3, for which the last ride has to be completed by 1 pm. Ride gates open every 30 minutes, e.g. 10 am, 10:30 am, and so on. Whenever a ride gate opens, and there is no visitor inside, the first visitor waiting in the queue buys the ticket just before taking the ride. The ticket prices are Rs. 20, Rs. 50, Rs. 30 and Rs. 40 for Rides 1 to 4, respectively. Each of the three visitors took at least one ride and did not necessarily take all rides. None of them took the same ride more than once. The movement time from one ride to another is negligible, and a visitor leaves the ride immediately after the completion of the ride. No one takes a break inside the park unless mentioned explicitly.

The following information is also known.

1. Chitra never waited in the queue and completed her visit by 11 am after spending Rs. 50 to pay for the ticket(s).

2. Anjali took Ride-1 at 11 am after waiting for 30 mins for Chitra to complete it. It was the only ride where Anjali waited.

3. Bipasha began her first of three rides at 11:30 am. All three visitors incurred the same amount of ticket expense by 12:15 pm.

4. The last ride taken by Anjali and Bipasha was the same, where Bipasha waited 30 mins for Anjali to complete her ride. Before standing in the queue for that ride, Bipasha took a 1-hour coffee break after completing her previous ride.

Q19 What was the total amount spent on tickets (in Rs.) by Bipasha? MCQ ▶

What was the total amount spent on tickets (in Rs.) by Bipasha?

A.

90

B.

120

C.

100

D.

110

Correct answer: D.

110

Step 1:

From conditions (1) and (2), it can be inferred that Chitra completed Ride 3 from 9:00 AM to 10:00 AM and Ride 1 from 10:00 AM to 11:00 AM. This follows because Anjali had to wait for 30 minutes to complete Ride 1, which finished at 11:00 AM.

From condition (3), Bipasha paid for only one ride until 12:15 PM, i.e., Ride 2, which ran from 11:30 AM to 12:30 PM. Since Bipasha completed three rides in total, she could not have taken Ride 3, as it ended at 1:00 PM.

The schedule at this stage is:

Anjali: Ride 1 – Unknown, Ride 2 – Unknown, Ride 3 – Unknown, Ride 4 – Unknown
Bipasha: Ride 2 – 11:30 AM to 12:30 PM, Ride 3 – Not taken
Chitra: Ride 1 – 10:00 AM to 11:00 AM, Ride 3 – 9:00 AM to 10:00 AM, Ride 2 and Ride 4 – Not taken

Step 2:

Using condition (4), Bipasha's schedule can be determined as follows:

11:30 AM – 12:30 PM: Ride 2
12:30 PM – 1:30 PM: Free
1:30 PM – 2:30 PM: Coffee break
2:30 PM – 3:00 PM: Waiting
3:00 PM – 4:00 PM: Ride 4

Since Bipasha waited from 2:30 PM to 3:00 PM for Anjali to complete the previous ride, her final ride started at 3:00 PM and ended at 4:00 PM.

Hence, the final schedule is:

Anjali
Ride 1: 11:00 AM – 12:00 PM
Ride 2: 1:00 PM – 2:00 PM
Ride 3: 12:00 PM – 1:00 PM
Ride 4: 2:00 PM – 3:00 PM
Bipasha
Ride 2: 11:30 AM – 12:30 PM
Ride 4: 3:00 PM – 4:00 PM
Chitra
Ride 1: 10:00 AM – 11:00 AM
Ride 3: 9:00 AM – 10:00 AM

Total amount spent on tickets (in Rs.) by Bipasha is Rs. 110.

Q20 Which ride was taken by all three visitors? MCQ ▶

Which ride was taken by all three visitors?

A.

Ride-4

B.

Ride-3

C.

Ride-2

D.

Ride-1

Correct answer: D.

Ride-1

Step 1:

From conditions (1) and (2), it can be inferred that Chitra completed Ride 3 from 9:00 AM to 10:00 AM and Ride 1 from 10:00 AM to 11:00 AM. This follows because Anjali had to wait for 30 minutes to complete Ride 1, which finished at 11:00 AM.

From condition (3), Bipasha paid for only one ride until 12:15 PM, i.e., Ride 2, which ran from 11:30 AM to 12:30 PM. Since Bipasha completed three rides in total, she could not have taken Ride 3, as it ended at 1:00 PM.

The schedule at this stage is:

Anjali: Ride 1 – Unknown, Ride 2 – Unknown, Ride 3 – Unknown, Ride 4 – Unknown
Bipasha: Ride 2 – 11:30 AM to 12:30 PM, Ride 3 – Not taken
Chitra: Ride 1 – 10:00 AM to 11:00 AM, Ride 3 – 9:00 AM to 10:00 AM, Ride 2 and Ride 4 – Not taken

Step 2:

Using condition (4), Bipasha's schedule can be determined as follows:

11:30 AM – 12:30 PM: Ride 2
12:30 PM – 1:30 PM: Free
1:30 PM – 2:30 PM: Coffee break
2:30 PM – 3:00 PM: Waiting
3:00 PM – 4:00 PM: Ride 4

Since Bipasha waited from 2:30 PM to 3:00 PM for Anjali to complete the previous ride, her final ride started at 3:00 PM and ended at 4:00 PM.

Hence, the final schedule is:

Anjali
Ride 1: 11:00 AM – 12:00 PM
Ride 2: 1:00 PM – 2:00 PM
Ride 3: 12:00 PM – 1:00 PM
Ride 4: 2:00 PM – 3:00 PM
Bipasha
Ride 2: 11:30 AM – 12:30 PM
Ride 4: 3:00 PM – 4:00 PM
Chitra
Ride 1: 10:00 AM – 11:00 AM
Ride 3: 9:00 AM – 10:00 AM

Ride 1 was taken by all three visitors.

Q21 Which were all the rides that Anjali completed by 2:00 pm? MCQ ▶

Which were all the rides that Anjali completed by 2:00 pm?

A.

Ride-1, Ride-2, and Ride-3

B.

Ride-1 and Ride-3

C.

Ride-1, Ride-2, and Ride-4

D.

Ride-1 and Ride-4

Correct answer: A.

Ride-1, Ride-2, and Ride-3

Step 1:

From conditions (1) and (2), it can be inferred that Chitra completed Ride 3 from 9:00 AM to 10:00 AM and Ride 1 from 10:00 AM to 11:00 AM. This follows because Anjali had to wait for 30 minutes to complete Ride 1, which finished at 11:00 AM.

From condition (3), Bipasha paid for only one ride until 12:15 PM, i.e., Ride 2, which ran from 11:30 AM to 12:30 PM. Since Bipasha completed three rides in total, she could not have taken Ride 3, as it ended at 1:00 PM.

The schedule at this stage is:

Anjali: Ride 1 – Unknown, Ride 2 – Unknown, Ride 3 – Unknown, Ride 4 – Unknown
Bipasha: Ride 2 – 11:30 AM to 12:30 PM, Ride 3 – Not taken
Chitra: Ride 1 – 10:00 AM to 11:00 AM, Ride 3 – 9:00 AM to 10:00 AM, Ride 2 and Ride 4 – Not taken

Step 2:

Using condition (4), Bipasha's schedule can be determined as follows:

11:30 AM – 12:30 PM: Ride 2
12:30 PM – 1:30 PM: Free
1:30 PM – 2:30 PM: Coffee break
2:30 PM – 3:00 PM: Waiting
3:00 PM – 4:00 PM: Ride 4

Since Bipasha waited from 2:30 PM to 3:00 PM for Anjali to complete the previous ride, her final ride started at 3:00 PM and ended at 4:00 PM.

Hence, the final schedule is:

Anjali
Ride 1: 11:00 AM – 12:00 PM
Ride 2: 1:00 PM – 2:00 PM
Ride 3: 12:00 PM – 1:00 PM
Ride 4: 2:00 PM – 3:00 PM
Bipasha
Ride 2: 11:30 AM – 12:30 PM
Ride 4: 3:00 PM – 4:00 PM
Chitra
Ride 1: 10:00 AM – 11:00 AM
Ride 3: 9:00 AM – 10:00 AM

The rides that Anjali completed by 2 pm are Ride 1, Ride 2 and Ride 3.

Q22 How many rides did Anjali and Chitra take in total? TITA ▶

How many rides did Anjali and Chitra take in total?

Answer: 6

Step 1:

From conditions (1) and (2), it can be inferred that Chitra completed Ride 3 from 9:00 AM to 10:00 AM and Ride 1 from 10:00 AM to 11:00 AM. This follows because Anjali had to wait for 30 minutes to complete Ride 1, which finished at 11:00 AM.

From condition (3), Bipasha paid for only one ride until 12:15 PM, i.e., Ride 2, which ran from 11:30 AM to 12:30 PM. Since Bipasha completed three rides in total, she could not have taken Ride 3, as it ended at 1:00 PM.

The schedule at this stage is:

Anjali: Ride 1 – Unknown, Ride 2 – Unknown, Ride 3 – Unknown, Ride 4 – Unknown
Bipasha: Ride 2 – 11:30 AM to 12:30 PM, Ride 3 – Not taken
Chitra: Ride 1 – 10:00 AM to 11:00 AM, Ride 3 – 9:00 AM to 10:00 AM, Ride 2 and Ride 4 – Not taken

Step 2:

Using condition (4), Bipasha's schedule can be determined as follows:

11:30 AM – 12:30 PM: Ride 2
12:30 PM – 1:30 PM: Free
1:30 PM – 2:30 PM: Coffee break
2:30 PM – 3:00 PM: Waiting
3:00 PM – 4:00 PM: Ride 4

Since Bipasha waited from 2:30 PM to 3:00 PM for Anjali to complete the previous ride, her final ride started at 3:00 PM and ended at 4:00 PM.

Hence, the final schedule is:

Anjali
Ride 1: 11:00 AM – 12:00 PM
Ride 2: 1:00 PM – 2:00 PM
Ride 3: 12:00 PM – 1:00 PM
Ride 4: 2:00 PM – 3:00 PM
Bipasha
Ride 2: 11:30 AM – 12:30 PM
Ride 4: 3:00 PM – 4:00 PM
Chitra
Ride 1: 10:00 AM – 11:00 AM
Ride 3: 9:00 AM – 10:00 AM

Anjali and Chitra take 6 Rides in total.

Q23 What was the total amount spent on tickets (in Rs.) by Anjali? TITA ▶

What was the total amount spent on tickets (in Rs.) by Anjali?

Answer: 140

Step 1:

From conditions (1) and (2), it can be inferred that Chitra completed Ride 3 from 9:00 AM to 10:00 AM and Ride 1 from 10:00 AM to 11:00 AM. This follows because Anjali had to wait for 30 minutes to complete Ride 1, which finished at 11:00 AM.

From condition (3), Bipasha paid for only one ride until 12:15 PM, i.e., Ride 2, which ran from 11:30 AM to 12:30 PM. Since Bipasha completed three rides in total, she could not have taken Ride 3, as it ended at 1:00 PM.

The schedule at this stage is:

Anjali: Ride 1 – Unknown, Ride 2 – Unknown, Ride 3 – Unknown, Ride 4 – Unknown
Bipasha: Ride 2 – 11:30 AM to 12:30 PM, Ride 3 – Not taken
Chitra: Ride 1 – 10:00 AM to 11:00 AM, Ride 3 – 9:00 AM to 10:00 AM, Ride 2 and Ride 4 – Not taken

Step 2:

Using condition (4), Bipasha's schedule can be determined as follows:

11:30 AM – 12:30 PM: Ride 2
12:30 PM – 1:30 PM: Free
1:30 PM – 2:30 PM: Coffee break
2:30 PM – 3:00 PM: Waiting
3:00 PM – 4:00 PM: Ride 4

Since Bipasha waited from 2:30 PM to 3:00 PM for Anjali to complete the previous ride, her final ride started at 3:00 PM and ended at 4:00 PM.

Hence, the final schedule is:

Anjali
Ride 1: 11:00 AM – 12:00 PM
Ride 2: 1:00 PM – 2:00 PM
Ride 3: 12:00 PM – 1:00 PM
Ride 4: 2:00 PM – 3:00 PM
Bipasha
Ride 2: 11:30 AM – 12:30 PM
Ride 4: 3:00 PM – 4:00 PM
Chitra
Ride 1: 10:00 AM – 11:00 AM
Ride 3: 9:00 AM – 10:00 AM

The total amount spent on tickets by Anjali is Rs. 140.

CAT — Conditional Reasoning

How many taps did Clive receive for his question?

Step 1:

Step 2:

Which two people tapped an equal number of times in total?

Step 1:

Step 2:

What was Clive’s response to Ehsaan’s question?

Step 1:

Step 2:

How many “Yes” responses were received across all the questions?

Step 1:

Step 2:

Step 1:

Step 2:

Step 1:

Step 2:

Step 1:

Step 2:

Step 1:

Step 2:

Step 1:

Step 2:

For which firm(s) can the amounts raised by them be concluded with certainty in each year?

Step 1:

What best can be concluded about the total amount of money raised in 2015?

Step 1:

Alfloo:

Elavalaki:

What is the largest possible total amount of money (in Rs. crores) that could have been raised in 2013?

If Elavalaki raised Rs. 3 crores in 2013, then what is the smallest possible total amount of money (in Rs. crores) that could have been raised by all the companies in 2012?

If the total amount of money raised in 2014 is Rs. 12 crores, then which of the following is not possible?

What was the total amount spent on tickets (in Rs.) by Bipasha?

Step 1:

Step 2:

Which ride was taken by all three visitors?

Step 1:

Step 2:

Which were all the rides that Anjali completed by 2:00 pm?

Step 1:

Step 2:

How many rides did Anjali and Chitra take in total?

Step 1:

Step 2:

What was the total amount spent on tickets (in Rs.) by Anjali?

Step 1:

Step 2:

Want this as a timed attempt?